先核來源與已訂規則
本例 A😀B 最多留兩個碼點。slice 按 UTF-16 編碼單位截,兩單位後只剩 A 及半組代理字元。先按有效 Unicode 字元逐項取,才留到 A😀;此約定不是按視覺字簇計。
| 紀錄 | 輸入 JSON |
|---|---|
| 原例輸入 | {"text":"A😀B","limit":2} |
比較兩條實際路徑
更正碼點為 65、128512,原標籤另留。錯尾碼卻是單個代理值 55357。
| 路徑 | 輸出 JSON |
|---|---|
| 錯誤路徑 | {"text":"A\ud83d","codePoints":[65,55357],"source":"A😀B"} |
| 更正路徑 | {"text":"A😀","codePoints":[65,128512],"source":"A😀B"} |
import {DatabaseSync} from 'node:sqlite';
import {TextDecoder} from 'node:util';
import {inflateSync} from 'node:zlib';
import {posix} from 'node:path';
import {createHash} from 'node:crypto';
const rows=(db,sql)=>db.prepare(sql).all().map(r=>({...r}));
const failed=(action)=>{try{action();return null;}catch(e){return {code:e.errcode??e.code??e.name};}};
import assert from 'node:assert/strict';
const run=function run(i,corrected=true){
if(!Number.isInteger(i.limit)||i.limit<0)return {accepted:false,error:'invalid-limit'};
const text=corrected?Array.from(i.text).slice(0,i.limit).join(''):i.text.slice(0,i.limit);
return {text,codePoints:Array.from(text).map(c=>c.codePointAt(0)),source:i.text};
};
const cases=[{"label":"misleading base","input":{"text":"A😀B","limit":2},"expected":{"text":"A\ud83d","codePoints":[65,55357],"source":"A😀B"},"corrected":false},{"label":"corrected base","input":{"text":"A😀B","limit":2},"expected":{"text":"A😀","codePoints":[65,128512],"source":"A😀B"},"corrected":true},{"label":"zero character allowance","input":{"text":"A😀B","limit":0},"expected":{"text":"","codePoints":[],"source":"A😀B"},"corrected":true},{"label":"exact full character length","input":{"text":"A😀B","limit":3},"expected":{"text":"A😀B","codePoints":[65,128512,66],"source":"A😀B"},"corrected":true}];
for(const test of cases){
const actual=run(test.input,test.corrected);
assert.deepEqual(actual,test.expected,test.label);
console.log(test.label,actual);
}
下次載入前核邊界
限零留空文字;限三則完整保留,毋須截字。
| 情況 | 輸入 JSON | 預期輸出 JSON |
|---|---|---|
| 零碼點配額 | {"text":"A😀B","limit":0} | {"text":"","codePoints":[],"source":"A😀B"} |
| 剛好全段長度 | {"text":"A😀B","limit":3} | {"text":"A😀B","codePoints":[65,128512,66],"source":"A😀B"} |
兩碼點上限應留哪個標籤?
查看參考答案
A😀,補充平面字元要完整保留,A 加半組代理字元不是所需結果。