先核來源與已訂規則
本例抽取約定要 R2 快取依據。公式 2+3 的快取卻是 R1 留下的 4,要暫停;例子不執行公式,也不能因看似易算便自行填新值。
| 紀錄 | 輸入 JSON |
|---|---|
| 原例輸入 | {"formula":"2+3","cache":4,"cacheRevision":"R1","requiredRevision":"R2"} |
比較兩條實際路徑
更正保留公式及快取 4,列明依據不足。符合本例版本的快取 5 可收;版本相符是此處收件門檻,不是所有公式均正確的證明。
| 路徑 | 輸出 JSON |
|---|---|
| 錯誤路徑 | {"accepted":true,"value":4,"formula":"2+3"} |
| 更正路徑 | {"accepted":false,"error":"cache-evidence-gap","formula":"2+3","retainedCache":4} |
import {DatabaseSync} from 'node:sqlite';
import {TextDecoder} from 'node:util';
import {inflateSync} from 'node:zlib';
import {posix} from 'node:path';
import {createHash} from 'node:crypto';
const rows=(db,sql)=>db.prepare(sql).all().map(r=>({...r}));
const failed=(action)=>{try{action();return null;}catch(e){return {code:e.errcode??e.code??e.name};}};
import assert from 'node:assert/strict';
const run=function run(i,corrected=true){
if(corrected&&(i.cache===null||i.cacheRevision!==i.requiredRevision))return {accepted:false,error:'cache-evidence-gap',formula:i.formula,retainedCache:i.cache};
return {accepted:true,value:i.cache,formula:i.formula};
};
const cases=[{"label":"misleading base","input":{"formula":"2+3","cache":4,"cacheRevision":"R1","requiredRevision":"R2"},"expected":{"accepted":true,"value":4,"formula":"2+3"},"corrected":false},{"label":"corrected base","input":{"formula":"2+3","cache":4,"cacheRevision":"R1","requiredRevision":"R2"},"expected":{"accepted":false,"error":"cache-evidence-gap","formula":"2+3","retainedCache":4},"corrected":true},{"label":"matching declared cache evidence","input":{"formula":"2+3","cache":5,"cacheRevision":"R2","requiredRevision":"R2"},"expected":{"accepted":true,"value":5,"formula":"2+3"},"corrected":true},{"label":"no cached result","input":{"formula":"2+3","cache":null,"cacheRevision":"R2","requiredRevision":"R2"},"expected":{"accepted":false,"error":"cache-evidence-gap","formula":"2+3","retainedCache":null},"corrected":true}];
for(const test of cases){
const actual=run(test.input,test.corrected);
assert.deepEqual(actual,test.expected,test.label);
console.log(test.label,actual);
}
下次載入前核邊界
R2 配快取 5 可收;沒有快取,即使標 R2 也要停。
| 情況 | 輸入 JSON | 預期輸出 JSON |
|---|---|---|
| 快取依據版本相符 | {"formula":"2+3","cache":5,"cacheRevision":"R2","requiredRevision":"R2"} | {"accepted":true,"value":5,"formula":"2+3"} |
| 尚無快取結果 | {"formula":"2+3","cache":null,"cacheRevision":"R2","requiredRevision":"R2"} | {"accepted":false,"error":"cache-evidence-gap","formula":"2+3","retainedCache":null} |
匯入程序可否自行把快取 4 換 5?
查看參考答案
不可,程序沒有執行公式或更新依據的步驟。先保留 4,補齊所需快取依據才收。