按指定終止鍵分清每次掃描

訂判斷及所需輸入

本例 ENTER 結束一次輸入，所需代碼三字。A12 ENTER B34 ENTER 是兩段；全拼字會丟界線，成 A12B34。若合字後才得一次 ENTER，就是一段超長輸入待查，不是已證實兩次掃描。

已填本地測試工作表
情況	輸入 JSON
原例測試	{"keys":["A","1","2","ENTER","B","3","4","ENTER"]}

下載可編輯 CSV ↓

跑所附比較

狀態程序只在指定終止鍵結段。分段收件與查清單不同，收到字不會自動建庫存移動。

錯誤及所需輸出
路徑	輸出 JSON
錯誤路徑	{"frames":["A12B34"],"pending":"","requiresReview":false}
所需路徑	{"frames":["A12","B34"],"pending":"","requiresReview":false}

下載可編輯 CSV ↓

完整本地 Node24.14.1 程序

import assert from 'node:assert/strict';

const run=function run(i,corrected=true){
    const frames=[];let pending='';for(const key of i.keys){if(key==='ENTER'){if(corrected){frames.push(pending);pending='';}}else pending+=key;}
    if(!corrected&&pending){frames.push(pending);pending='';}
    return {frames,pending,requiresReview:corrected&&(pending!==''||frames.some(f=>f.length!==3))};
  };
const cases=[{"input":{"keys":["A","1","2","ENTER","B","3","4","ENTER"]},"corrected":false,"expected":{"frames":["A12B34"],"pending":"","requiresReview":false}},{"input":{"keys":["A","1","2","ENTER","B","3","4","ENTER"]},"corrected":true,"expected":{"frames":["A12","B34"],"pending":"","requiresReview":false}},{"input":{"keys":["A","1","2","B","3","4","ENTER"]},"corrected":true,"expected":{"frames":["A12B34"],"pending":"","requiresReview":true}},{"input":{"keys":["A","1","2"]},"corrected":true,"expected":{"frames":[],"pending":"A12","requiresReview":true}}];
for(const test of cases){const actual=await run(test.input,test.corrected);assert.deepEqual(actual,test.expected);console.log(actual);}

下載可執行例子 ↓

按邊界依據作判斷

A12 未有終止鍵仍待完；六字完整段照留一段，列須覆核。

字元先放待完段
指定終止鍵才結段
查清單前先核段長

不能因代碼外觀熟悉就補終止鍵。

可編輯邊界輸入及結果
條件	輸入 JSON	預期輸出 JSON
只有一個合併段	{"keys":["A","1","2","B","3","4","ENTER"]}	{"frames":["A12B34"],"pending":"","requiresReview":true}
尾段未有終止鍵	{"keys":["A","1","2"]}	{"frames":[],"pending":"A12","requiresReview":true}

下載可編輯 CSV ↓

合段可否自動拆回 A12、B34？

查看參考答案

不能，只有一次終止鍵。A12B34 留作一段未解輸入，先補分段依據。

訂判斷及所需輸入

跑所附比較

按邊界依據作判斷

相關資源