訂判斷及所需輸入
題內網絡2 秒、伺服器3、客戶端呈現4。只量伺服器是3,用戶完成是9。原例要求用戶完成,伺服器數字不能代替該量法。
| 情況 | 輸入 JSON |
|---|---|
| 原例測試 | {"scope":"user-complete","seconds":{"network":2,"server":3,"render":4}} |
跑所附比較
程序只按所需範圍加題內已觀察段,不補未知段,也未確認真系統量到了所有可能延遲。
| 路徑 | 輸出 JSON |
|---|---|
| 錯誤路徑 | {"scope":"user-complete","measuredSeconds":3} |
| 所需路徑 | {"scope":"user-complete","measuredSeconds":9} |
import assert from 'node:assert/strict';
const run=function run(i,corrected=true){
if(!['server','user-complete'].includes(i.scope)||['network','server','render'].some(k=>!Number.isFinite(i.seconds[k])||i.seconds[k]<0))return {held:true};
const total=i.seconds.network+i.seconds.server+i.seconds.render;
return {scope:i.scope,measuredSeconds:corrected&&i.scope==='user-complete'?total:i.seconds.server};
};
const cases=[{"input":{"scope":"user-complete","seconds":{"network":2,"server":3,"render":4}},"corrected":false,"expected":{"scope":"user-complete","measuredSeconds":3}},{"input":{"scope":"user-complete","seconds":{"network":2,"server":3,"render":4}},"corrected":true,"expected":{"scope":"user-complete","measuredSeconds":9}},{"input":{"scope":"server","seconds":{"network":2,"server":3,"render":4}},"corrected":true,"expected":{"scope":"server","measuredSeconds":3}},{"input":{"scope":"user-complete","seconds":{"network":2,"server":3,"render":null}},"corrected":true,"expected":{"held":true}}];
for(const test of cases){const actual=await run(test.input,test.corrected);assert.deepEqual(actual,test.expected);console.log(actual);}
按邊界依據作判斷
明訂伺服器範圍就正當得3;呈現時間欠缺,完整比較要停,不拿別次紀錄猜9。
- 訂量度起終點
- 取各所需時間段
- 按該範圍報時長
所需段未觀察到就停,不能當零。
| 條件 | 輸入 JSON | 預期輸出 JSON |
|---|---|---|
| 只量伺服器段 | {"scope":"server","seconds":{"network":2,"server":3,"render":4}} | {"scope":"server","measuredSeconds":3} |
| 尚未觀察呈現時間 | {"scope":"user-complete","seconds":{"network":2,"server":3,"render":null}} | {"held":true} |
原例用戶完成目標,應是哪個時長?
查看參考答案
九秒,2+3+4。三秒只是伺服器段,須保該較窄標記。