訂明候選檔案空白時怎樣評

訂明本例驗收任務

假設批次評分每個已訂個案須有一個候選。先核欠及多編號才評內容。預期清單空白屬定義無效；預期三題而候選空白是未完整，不能因迴圈沒失敗就當通過。

先核非空預期清單
找欠及多候選編號
齊備才進內容評分

覆蓋欠項仍未完整，不補造候選結果。

使用已填個案

原創假設輸入及確切答案鍵
個案	已提供輸入	預期結構化結果	判斷及原因
候選檔案空白	{"expected":["C1","C2","C3"],"candidates":[]}	{"status":"incomplete","missing":["C1","C2","C3"],"extra":[]}	欠全部三個候選，未能計內容通過率。
所需編號齊備	{"expected":["C1","C2"],"candidates":["C2","C1"]}	{"status":"ready-to-grade","missing":[],"extra":[]}	覆蓋齊備，內容評分是之後一步。
預期個案清單空白	{"expected":[],"candidates":[]}	{"status":"invalid-definition"}	空白定義不能證明已完整驗收。

下載可編輯 CSV ↓

逐步處理 no-evaluation-definition 個案，須得到甚麼結果？原因是甚麼？

查看參考答案

{"status":"invalid-definition"}。空白定義不能證明已完整驗收。

執行完整本機驗算

另存為 .mjs，以 Node.js 執行；只驗提供的個案

import assert from 'node:assert/strict';

function evaluate(x){
 if(!x.expected.length)return {status:'invalid-definition'};const missing=x.expected.filter(id=>!x.candidates.includes(id)).sort(),extra=x.candidates.filter(id=>!x.expected.includes(id)).sort();
 return {status:missing.length+extra.length?'incomplete':'ready-to-grade',missing,extra};
}

const cases = [
  {
    "id": "empty-candidates",
    "input": {
      "expected": [
        "C1",
        "C2",
        "C3"
      ],
      "candidates": []
    },
    "expected": {
      "status": "incomplete",
      "missing": [
        "C1",
        "C2",
        "C3"
      ],
      "extra": []
    }
  },
  {
    "id": "full-candidates",
    "input": {
      "expected": [
        "C1",
        "C2"
      ],
      "candidates": [
        "C2",
        "C1"
      ]
    },
    "expected": {
      "status": "ready-to-grade",
      "missing": [],
      "extra": []
    }
  },
  {
    "id": "no-evaluation-definition",
    "input": {
      "expected": [],
      "candidates": []
    },
    "expected": {
      "status": "invalid-definition"
    }
  }
];
for (const c of cases) assert.deepEqual(evaluate(c.input), c.expected, c.id);
console.log(JSON.stringify({checked:cases.length,caseIds:cases.map(c=>c.id)}));

下載可執行例子 ↓

此步前另查重複鍵。可進評分不等於任何候選內容已通過。

訂明本例驗收任務

使用已填個案

執行完整本機驗算

相關資源