Split completed and unstarted units
Synthetic order O-166 has ten task units: four completed and six unstarted. A requested total of seven can retain four completed units and leave three unstarted, reducing three. A requested total of three is below completed work and cannot be represented as a simple quantity reduction. The fixture excludes in-progress tasks, payments and fees; those require their own decisions.
| Requested total | Completed retained | Unstarted after change | Decision |
|---|---|---|---|
| 7 | 4 | 3 = 7 − 4 | Eligible reduction of 3 |
| 4 | 4 | 0 | Remove all 6 unstarted units |
| 3 | 4 already completed | Not a valid negative remainder | Escalate scope discrepancy |
Check the completed floor before changing quantity
- Read current total and completion
- Compare requested total with completed units
- Compute remaining unstarted units
- Confirm amendment baseline
If work is in progress, this simple fixture cannot classify it as unstarted; collect its status before calculating a reduction.
Why is reducing ten units to seven not a six-unit cancellation?
Show the worked answer
The total reduction is 10 − 7 = 3. Six were unstarted, but three remain required after retaining four completed units.
The completed floor is an operating assumption, not a statement about refund rights or billable amounts.